﻿ pochodna sin(x)/x

# pochodna sin(x)/x

sin x sin 2x sin 3x sin 4x sin nx. by cos( kx) or by sin( kx) and use the results 1 through 7, we get the value of the various Fourier coefficients given above. Solved Problem 1 Sin4xcosx sinxcos4x sin4xcosx - sinxcos4x. 2sinxcos4x 0 divide both sides by 2. Sinxcos4 x 0. So either. Sinx 0 which happens at 0 nPi where n is an integer. Use loglog(): Import numpy as np import scipy as sp import matplotlib as mpl import matplotlib.pyplot as plt. Def derivative1( x, h): return (sp.sin(x h) - sp.sin(x)) / h. Def derivative2(x, h): return (sp. sin(x (0.5 h)) - sp.sin(x - (0.5 h))) / h. Def derivative3(x, h): return (sp. sin(x - 2 h) - 8 sp.sin(x - h) 8 The C floating point function is fabs. After changing your three lines to. w1 log 10(fabs(metodapochodna1(x,h) - kos)) w2 log10(fabs(metodapochodna2(x,h) - kos)) w3 log 10(fabs(metodapochodna3(x,h) - kos)) the program outputs more sensible values. Answer: The right hand side should be - cos x Expand sin(x-pi/2) using sin(a-b)sin a cos b-cos a sin b.

10 minutes ago. know this is implicit differentiation and that displaystylefracdydx of displaystyle sin(xy) is displaystyle ycos(xy) but how is this done with x y. Now lets look at the graph of y 5 sin x. This time we have amplitude 5 and period 2. (I have used a different scale on the y-axis.